Loading...
Which among the following is the smallest \(\mathrm{7}\) digit number that is exactly divisible by \(\mathrm{43}\)?
Let's break down what we're looking for. We need the smallest 7-digit number that is exactly divisible by 43.
The smallest 7-digit number is \(1,000,000\) (one followed by six zeros). However, this number might not be divisible by 43. If it's not divisible by 43, we need to find the next number larger than \(1,000,000\) that IS divisible by 43.
Think of it like this: imagine you're looking for parking spaces numbered in multiples of 43, and you need the first space that's numbered \(1,000,000\) or higher. If space \(1,000,000\) isn't a multiple of 43, you need to walk forward until you find the next multiple.
Process Skill: TRANSLATE - Converting the word problem into a clear mathematical task
Now we need to see what happens when we divide \(1,000,000\) by 43.
Let's do this division step by step:
\(1,000,000 \div 43 = ?\)
To find this, I'll calculate: \(1,000,000 \div 43 = 23,255\) with a remainder.
Let me verify: \(23,255 \times 43 = 999,965\)
So when we divide \(1,000,000\) by 43:
This means \(1,000,000 = 43 \times 23,255 + 35\)
The remainder is 35, which tells us that \(1,000,000\) is 35 more than the nearest smaller multiple of 43.
Since \(1,000,000\) has a remainder of 35 when divided by 43, we need to add something to get to the next multiple of 43.
Think about it this way: if we've gone 35 steps past a multiple of 43, how many more steps do we need to reach the NEXT multiple of 43?
We need: \(43 - 35 = 8\) more steps.
So the smallest 7-digit number divisible by 43 is:
\(1,000,000 + 8 = 1,000,008\)
Let's verify: The next multiple of 43 after 999,965 would be:
\(999,965 + 43 = 1,000,008\) ✓
Looking at our answer choices:
Let's double-check that \(1,000,008\) is divisible by 43:
\(1,000,008 \div 43 = 23,256\) exactly (no remainder)
Verification: \(23,256 \times 43 = 1,000,008\) ✓
The answer is B. 1,000,008.
Students might confuse themselves about what exactly is the smallest 7-digit number. Some may think it's 1,111,111 or get confused about counting digits properly. The smallest 7-digit number is definitively \(1,000,000\) (one followed by six zeros), but this foundational step needs to be crystal clear.
2. Not recognizing this as a "find the next multiple" problemThe key insight is understanding that we need to find the smallest multiple of 43 that is greater than or equal to \(1,000,000\). Students might try to approach this by testing each answer choice individually rather than using the systematic approach of finding the remainder and calculating the adjustment needed.
When dividing \(1,000,000\) by 43, students are prone to calculation errors. The division \(1,000,000 \div 43 = 23,255\) remainder 35 involves multiple steps, and any mistake in the multiplication (\(23,255 \times 43 = 999,965\)) or subtraction (\(1,000,000 - 999,965 = 35\)) will lead to an incorrect remainder.
2. Incorrect calculation of the adjustment neededOnce students find that \(1,000,000\) leaves a remainder of 35 when divided by 43, they need to calculate \(43 - 35 = 8\) to find how much to add. Some students mistakenly think they should subtract the remainder instead of finding the complement, or they might add the remainder itself (35) instead of the complement (8).
After calculating \(1,000,000 + 8 = 1,000,008\), students should verify that this number is actually divisible by 43. Skipping this verification step means missing the chance to catch any earlier calculation errors. Students should confirm that \(1,000,008 \div 43 = 23,256\) with no remainder.