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The range of a set of measurements is \(112.4\). If each measurement in the set is increased by \(10\) and then divided by \(4\), what will be the range of the resulting set of measurements?
Let's start by understanding what "range" means in everyday terms. Think of range as the "spread" of your data - it's simply how far apart your highest and lowest values are.
For example, if your test scores were \(70, 75, 80, 85, 90\), then:
So when the problem tells us "the range of a set of measurements is \(112.4\)," it means that if we took the biggest measurement and subtracted the smallest measurement, we'd get \(112.4\).
We don't need to know what the actual measurements are - we just need to understand how transformations affect this "spread" between the highest and lowest values.
Process Skill: TRANSLATE - Converting the problem language into mathematical understanding
Now let's think about what happens when we add the same number (\(10\)) to every measurement.
Imagine you have those test scores again: \(70, 75, 80, 85, 90\).
If we add \(10\) to each score: \(80, 85, 90, 95, 100\).
Notice what happened:
The range stayed exactly the same! This makes perfect sense when you think about it - we're shifting all the numbers by the same amount, so the "gap" between the highest and lowest stays the same.
This is like moving a group of people - if everyone takes \(10\) steps forward together, the distance between the person at the front and the person at the back doesn't change.
So after adding \(10\) to each measurement in our problem, the range is still \(112.4\).
Next, let's see what happens when we divide every measurement by the same number (\(4\)).
Let's continue with our example. We had: \(80, 85, 90, 95, 100\) after adding \(10\).
Now divide each by \(4\): \(20, 21.25, 22.5, 23.75, 25\).
Let's check the range:
Notice that \(5 = 20 \div 4\). The range got divided by the same number we used to divide all the measurements!
This makes intuitive sense too - if we shrink everything by the same factor, then the distance between any two points also gets shrunk by that same factor.
So in our problem, when we divide each measurement by \(4\), the range of \(112.4\) becomes: \(112.4 \div 4 = 28.1\)
Let's put it all together step by step:
We can verify this with our general understanding:
Therefore: New range = \(112.4 \div 4 = 28.1\)
The range of the resulting set of measurements will be \(28.1\).
Looking at our answer choices, this matches choice E.
Answer: E. \(28.1\)
Faltering Point 1: Misunderstanding what "range" means
Students might confuse range with other statistical measures like mean, median, or standard deviation. They may try to calculate how these other measures change with the transformations, rather than focusing on the simple difference between maximum and minimum values.
Faltering Point 2: Thinking they need the actual data values
Students often get stuck thinking they need to know the specific measurements in the set to solve this problem. They might try to create sample data or feel frustrated that the problem doesn't give them the actual numbers, not realizing that range transformations follow predictable patterns regardless of the specific values.
Faltering Point 3: Misunderstanding the sequence of operations
Students might misread the problem and think they need to divide by \(4\) first, then add \(10\), rather than the correct sequence of adding \(10\) first, then dividing by \(4\). This confusion about order of operations will lead to incorrect analysis of how the range changes.
Faltering Point 1: Incorrectly applying the addition transformation
Students might think that adding \(10\) to each measurement also adds \(10\) to the range. They would calculate: new range = \(112.4 + 10 = 122.4\), failing to understand that adding the same constant to all values shifts the entire dataset but doesn't change the spread.
Faltering Point 2: Arithmetic errors in division
When dividing \(112.4\) by \(4\), students might make simple calculation errors, potentially getting \(28.6\) instead of \(28.1\), or other incorrect decimal results. This is especially common when working under time pressure.
Faltering Point 3: Applying transformations in wrong order to the range
Even if students understand the individual effects, they might apply them incorrectly to the range calculation. For example, they might calculate \((112.4 + 10) \div 4 = 30.6\), incorrectly thinking that both operations affect the range.
Faltering Point 1: Choosing the intermediate calculation result
Students who incorrectly calculated \((112.4 + 10) \div 4 = 30.6\) might select answer choice D (\(30.6\)), not realizing they made an error in their approach to how transformations affect range.
Faltering Point 2: Selecting the original range value
Students who get confused about whether any transformation actually changes the range might default to choosing answer C (\(112.4\)), thinking that somehow the range remains completely unchanged by all the operations.