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Machines X and Y run at different constant rates, and machine X can complete a certain job in 9 hours. Machine X worked on the job alone for the first 3 hours and the two machines, working together, then completed the job in 4 more hours. How many hours would it have taken machine Y, working alone, to complete the entire job?
Let's break down what's happening in this problem step by step:
We have two machines, X and Y, that work at different speeds. Think of this like two people painting a house - one might be faster than the other.
Here's what we know:
The key insight is to think about work in terms of "what fraction of the job gets done each hour." If X can finish the whole job in 9 hours, then X completes \(\frac{1}{9}\) of the job each hour it works.
Process Skill: TRANSLATE - Converting the problem description into clear mathematical relationships
Now let's figure out how much work X accomplished in those first 3 hours working by itself.
Since X completes \(\frac{1}{9}\) of the job each hour, in 3 hours X completes:
\(3 \text{ hours} \times \frac{1}{9} \text{ job per hour} = \frac{3}{9} = \frac{1}{3}\) of the total job
This means after X works alone for 3 hours, there's still \(\frac{2}{3}\) of the job remaining to be completed.
We can verify this makes sense: if \(\frac{1}{3}\) of the job is done, then \(1 - \frac{1}{3} = \frac{2}{3}\) remains.
Next, both machines work together for 4 hours to finish the remaining \(\frac{2}{3}\) of the job.
During these 4 hours of combined work:
So in 4 hours of working together:
X completes: \(4 \times \frac{1}{9} = \frac{4}{9}\) of the job
Y completes: \(4 \times \frac{1}{t} = \frac{4}{t}\) of the job
The total work they do together must equal the remaining \(\frac{2}{3}\):
\(\frac{4}{9} + \frac{4}{t} = \frac{2}{3}\)
Now we solve for t (the time Y needs to complete the entire job alone):
\(\frac{4}{9} + \frac{4}{t} = \frac{2}{3}\)
Subtract \(\frac{4}{9}\) from both sides:
\(\frac{4}{t} = \frac{2}{3} - \frac{4}{9}\)
To subtract these fractions, we need a common denominator. The LCD of 3 and 9 is 9:
\(\frac{4}{t} = \frac{6}{9} - \frac{4}{9} = \frac{2}{9}\)
Now we can solve for t:
\(\frac{4}{t} = \frac{2}{9}\)
Cross multiply: \(4 \times 9 = 2 \times t\)
\(36 = 2t\)
\(t = 18\)
Let's verify this makes sense: If Y takes 18 hours to do the whole job alone, then Y works at a rate of \(\frac{1}{18}\) job per hour. In the 4 hours of combined work, Y would complete \(4 \times \frac{1}{18} = \frac{4}{18} = \frac{2}{9}\) of the job, which matches our calculation above.
Machine Y, working alone, would take 18 hours to complete the entire job.
This corresponds to answer choice (A) 18.
Verification: Total work done = Work by X alone + Work by X and Y together = \(\frac{1}{3} + \frac{2}{3} = 1\) complete job ✓
Faltering Point 1: Misunderstanding the work sequence
Students often misinterpret the problem setup and think that X and Y work together for the entire 7 hours (3 + 4), rather than understanding that X works alone for 3 hours first, then both machines work together for 4 hours. This leads to setting up the wrong equation from the start.
Faltering Point 2: Confusion about what represents "the job"
Some students get confused about what constitutes "the entire job" versus "remaining work." They might try to set up equations where the 4 hours of combined work represents completing the entire job, rather than just the remaining \(\frac{2}{3}\) of the job after X worked alone.
Faltering Point 1: Arithmetic errors when working with fractions
Students frequently make mistakes when subtracting fractions like \(\frac{2}{3} - \frac{4}{9}\). They might forget to find the common denominator (9), or incorrectly calculate \(\frac{6}{9} - \frac{4}{9}\), leading to wrong values for Y's work rate and ultimately the wrong final answer.
Faltering Point 2: Cross-multiplication errors
When solving \(\frac{4}{t} = \frac{2}{9}\), students sometimes make errors in cross-multiplication. They might incorrectly write \(4 \times 2 = 9 \times t\) instead of \(4 \times 9 = 2 \times t\), or make basic arithmetic mistakes when calculating \(4 \times 9 = 36\).
Faltering Point 1: Selecting Y's rate instead of Y's time
After correctly calculating that Y works at a rate of \(\frac{1}{18}\) jobs per hour, some students mistakenly look for \(\frac{1}{18}\) among the answer choices instead of recognizing that the question asks for the time (18 hours) it would take Y to complete the entire job alone.