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In a certain medical survey, \(45\%\) of the people surveyed had the type A antigen in their blood and \(3\%\) had both the type A antigen and the type B antigen. Which of the following is closest to the percent of those with the type A antigen who also had the type B antigen?
The question asks: "Which of the following is closest to the percent of those with the type A antigen who also had the type B antigen?" In other words, of all people with type A, what fraction also have type B?
Of the 45 people (per 100) with type A, 3 have both. So we compute 3 ÷ 45.
\(3 \div 45 = \frac{1}{15} = 0.0667…\)
\(0.0667 \times 100\% = 6.67\%\)
6.67% (answer choice B)