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If \(\mathrm{x} < \mathrm{y} < \mathrm{z}\) and \(\mathrm{y} - \mathrm{x} > 5\), where \(\mathrm{x}\) is an even integer and \(\mathrm{y}\) and \(\mathrm{z}\) are odd integers, what is the least possible value of \(\mathrm{z} - \mathrm{x}\)?
Let's break down what we need to find step by step. We want the smallest possible value of \(\mathrm{z - x}\), which is the difference between our largest and smallest numbers.
Here are our constraints in plain English:
Mathematically: \(\mathrm{x < y < z, y - x > 5}\), x is even, y and z are odd
Process Skill: TRANSLATE - Converting the word problem into clear mathematical constraints
Now let's think about the smallest possible difference between y and x. We know that \(\mathrm{y - x > 5}\), which means \(\mathrm{y - x}\) must be at least 6.
But wait - there's something important to consider here. Since x is even and y is odd, let's think about what happens when we subtract an even number from an odd number. The result is always odd!
For example:
Since \(\mathrm{y - x}\) must be greater than 5 AND must be odd (because odd minus even equals odd), the smallest possible value for \(\mathrm{y - x}\) is 7.
Let's verify with an example: If \(\mathrm{x = 2}\), then y must be at least \(\mathrm{2 + 7 = 9}\).
Process Skill: INFER - Recognizing that the parity (even/odd nature) of numbers creates additional constraints
Now let's look at the gap between y and z. We know that \(\mathrm{y < z}\) and both are odd integers.
Since both y and z are odd, what's the smallest possible difference? Well, if we start with any odd number, the very next odd number is 2 more. For example:
So the minimum value for \(\mathrm{z - y}\) is 2.
Now we can put it all together! We want to find the minimum value of \(\mathrm{z - x}\).
We can think of this as: \(\mathrm{z - x = (z - y) + (y - x)}\)
From our work above:
Therefore, the minimum value of \(\mathrm{z - x = 7 + 2 = 9}\)
Let's verify with a concrete example:
Process Skill: APPLY CONSTRAINTS - Systematically combining all constraints to find the minimum possible value
The least possible value of \(\mathrm{z - x}\) is 9.
Looking at our answer choices:
The answer is D. 9.
Students often interpret "\(\mathrm{y - x > 5}\)" as "\(\mathrm{y - x ≥ 5}\)", thinking the minimum difference can be exactly 5. This leads them to incorrectly assume that \(\mathrm{y - x}\) can equal 5, when it must actually be greater than 5.
2. Overlooking the parity constraint between even and odd integersMany students fail to recognize that when subtracting an even integer from an odd integer (\(\mathrm{y - x}\)), the result must always be odd. They might think \(\mathrm{y - x}\) could be 6 (the smallest integer greater than 5) without realizing that 6 is even and therefore impossible given the constraints.
3. Attempting to minimize each variable individually rather than the target expressionStudents sometimes try to find the smallest possible values for x, y, and z separately, rather than focusing on minimizing the specific expression \(\mathrm{z - x}\). This can lead to suboptimal combinations that don't actually minimize the target difference.
When determining that \(\mathrm{y - x}\) must be odd and greater than 5, students might incorrectly conclude the minimum is 5 or 6, forgetting that the next odd number after 5 is 7. They may also make arithmetic errors when adding constraints.
2. Wrong gap calculation between consecutive odd integersStudents sometimes think consecutive odd integers differ by 1 (like consecutive integers) rather than 2. For example, they might think if \(\mathrm{y = 9}\), then z could be 10, forgetting that z must also be odd.
Students might select 7 (the minimum value of \(\mathrm{y - x}\)) or 2 (the minimum value of \(\mathrm{z - y}\)) instead of their sum, which gives the minimum value of \(\mathrm{z - x = 9}\). They lose track of what the question is actually asking for.
Instead of working with general variables, we can find the minimum value of \(\mathrm{z - x}\) by choosing the smallest possible concrete values that satisfy all constraints.
Step 1: Choose the smallest convenient value for x
Since x must be even, let's use \(\mathrm{x = 0}\) (the smallest non-negative even integer for simplicity).
Step 2: Find the smallest possible y
We need \(\mathrm{y - x > 5}\), so \(\mathrm{y - 0 > 5}\), which means \(\mathrm{y > 5}\).
Since y must be odd and \(\mathrm{y > 5}\), the smallest possible value is \(\mathrm{y = 7}\).
Check: \(\mathrm{y - x = 7 - 0 = 7 > 5}\) ✓
Step 3: Find the smallest possible z
We need \(\mathrm{z > y}\) and z must be odd.
Since \(\mathrm{y = 7}\) and \(\mathrm{z > 7}\) with z odd, the smallest possible value is \(\mathrm{z = 9}\).
Step 4: Calculate z - x
\(\mathrm{z - x = 9 - 0 = 9}\)
Verification with different starting point:
Let's verify with \(\mathrm{x = 2}\):
The pattern holds: regardless of which even integer we choose for x, the minimum value of \(\mathrm{z - x}\) is always 9.