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If \(\mathrm{x}^2 + \frac{1}{\mathrm{x}^2} = 4\), what is the value of \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4}\) ?
Let's start by understanding what we have and what we need to find. We're given that \(\mathrm{x}^2 + \frac{1}{\mathrm{x}^2} = 4\), and we need to find \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4}\).
Think of this like a puzzle where we have one piece of information and need to use it to find another related piece. The key insight is that these expressions are connected - if we know something about \(\mathrm{x}^2 + \frac{1}{\mathrm{x}^2}\), we should be able to figure out something about \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4}\).
Process Skill: TRANSLATE - Converting the given condition into a form we can work with algebraically
Here's the crucial insight: notice that \(\mathrm{x}^4\) is the same as \((\mathrm{x}^2)^2\), and \(\frac{1}{\mathrm{x}^4}\) is the same as \((\frac{1}{\mathrm{x}^2})^2\). This means we can think of \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4}\) as \((\mathrm{x}^2)^2 + (\frac{1}{\mathrm{x}^2})^2\).
So if we let \(\mathrm{y} = \mathrm{x}^2\) and \(\mathrm{z} = \frac{1}{\mathrm{x}^2}\), then:
This transforms our problem from working with fourth powers to working with squares, which is much more manageable.
Now we use a fundamental algebraic relationship. When we square a sum, we get:
\((\mathrm{y} + \mathrm{z})^2 = \mathrm{y}^2 + 2\mathrm{yz} + \mathrm{z}^2\)
Substituting back our expressions:
\((\mathrm{x}^2 + \frac{1}{\mathrm{x}^2})^2 = (\mathrm{x}^2)^2 + 2(\mathrm{x}^2)(\frac{1}{\mathrm{x}^2}) + (\frac{1}{\mathrm{x}^2})^2\)
\((\mathrm{x}^2 + \frac{1}{\mathrm{x}^2})^2 = \mathrm{x}^4 + 2 + \frac{1}{\mathrm{x}^4}\)
Notice that the middle term \(2(\mathrm{x}^2)(\frac{1}{\mathrm{x}^2}) = 2(1) = 2\), since \(\frac{\mathrm{x}^2}{\mathrm{x}^2} = 1\).
So we have: \((\mathrm{x}^2 + \frac{1}{\mathrm{x}^2})^2 = \mathrm{x}^4 + \frac{1}{\mathrm{x}^4} + 2\)
Rearranging to isolate what we want:
\(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4} = (\mathrm{x}^2 + \frac{1}{\mathrm{x}^2})^2 - 2\)
Process Skill: MANIPULATE - Using algebraic identities to connect the given expression to our target
Now we substitute the known value:
\(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4} = (4)^2 - 2\)
\(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4} = 16 - 2\)
\(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4} = 14\)
Let's verify this makes sense: we started with \(\mathrm{x}^2 + \frac{1}{\mathrm{x}^2} = 4\), and found that \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4} = 14\). Since we're dealing with fourth powers instead of second powers, it's reasonable that our answer is larger than 4.
The value of \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4}\) is 14.
Looking at our answer choices: A. 2, B. 4, C. 6, D. 14, E. 16
Our answer matches choice D. 14.
1. Attempting to solve for x first
Many students see \(\mathrm{x}^2 + \frac{1}{\mathrm{x}^2} = 4\) and immediately try to solve for the actual values of x. They might set up a quadratic equation or try to find specific values like \(\mathrm{x} = ±\sqrt{2}\). This approach, while mathematically possible, is unnecessarily complex and time-consuming. The elegant solution recognizes that we don't need to know x's value - we can work directly with the given expression.
2. Missing the algebraic relationship between the expressions
Students often fail to see that \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4}\) can be written as \((\mathrm{x}^2)^2 + (\frac{1}{\mathrm{x}^2})^2\), which directly relates to the given condition \(\mathrm{x}^2 + \frac{1}{\mathrm{x}^2} = 4\). Without this key insight, they may attempt various unproductive approaches or even conclude the problem cannot be solved with the given information.
3. Not recognizing the squaring identity pattern
Even if students see the connection between \(\mathrm{x}^2 + \frac{1}{\mathrm{x}^2}\) and \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4}\), they may not realize they should use the identity \((\mathrm{a} + \mathrm{b})^2 = \mathrm{a}^2 + 2\mathrm{ab} + \mathrm{b}^2\). Instead, they might try to manipulate the expressions in other ways, leading to dead ends.
1. Algebraic manipulation errors in the squaring formula
When applying \((\mathrm{x}^2 + \frac{1}{\mathrm{x}^2})^2 = (\mathrm{x}^2)^2 + 2(\mathrm{x}^2)(\frac{1}{\mathrm{x}^2}) + (\frac{1}{\mathrm{x}^2})^2\), students commonly make errors in the middle term. They might incorrectly calculate \(2(\mathrm{x}^2)(\frac{1}{\mathrm{x}^2})\) as something other than 2, or forget this term entirely, leading to \((\mathrm{x}^2 + \frac{1}{\mathrm{x}^2})^2 = \mathrm{x}^4 + \frac{1}{\mathrm{x}^4}\) instead of \((\mathrm{x}^2 + \frac{1}{\mathrm{x}^2})^2 = \mathrm{x}^4 + \frac{1}{\mathrm{x}^4} + 2\).
2. Sign errors in rearrangement
When rearranging \((\mathrm{x}^2 + \frac{1}{\mathrm{x}^2})^2 = \mathrm{x}^4 + \frac{1}{\mathrm{x}^4} + 2\) to isolate \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4}\), students may incorrectly write \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4} = (\mathrm{x}^2 + \frac{1}{\mathrm{x}^2})^2 + 2\) instead of \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4} = (\mathrm{x}^2 + \frac{1}{\mathrm{x}^2})^2 - 2\). This sign error would lead to the incorrect answer of 18.
1. Arithmetic calculation mistakes
Even with the correct setup \(\mathrm{x}^4 + \frac{1}{\mathrm{x}^4} = (4)^2 - 2\), students may make simple arithmetic errors. They might calculate \(4^2\) as 8 instead of 16, or make errors in the final subtraction \(16 - 2\), potentially arriving at incorrect values like 12 or 16. These computational slips can lead them to select wrong answer choices.