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If two \(\mathrm{2}\)-digit positive integers have their respective tens digits exchanged, the difference between the pair of integers changes by \(\mathrm{4}\). What is the greatest possible difference between the original pair of integers?
Let's start by understanding what we have in everyday terms. We have two 2-digit positive integers - let's call them our "first number" and "second number."
When we exchange (swap) their tens digits with each other, something interesting happens: the difference between these two numbers changes by exactly 4.
For example, if we started with numbers 35 and 72, after swapping tens digits we'd get 75 and 32. The original difference was \(|35 - 72| = 37\), and the new difference is \(|75 - 32| = 43\). The change in difference is \(43 - 37 = 6\). But we need this change to be exactly 4.
Our goal is to find the maximum possible original difference between two such numbers that satisfy this condition.
Process Skill: TRANSLATE - Converting the problem's verbal description into a clear mathematical understanding
Now let's represent our two numbers mathematically. Any 2-digit number can be written as 10 times its tens digit plus its units digit.
Let's call our first number: \(10\mathrm{a} + \mathrm{b}\) (where 'a' is the tens digit and 'b' is the units digit)
Let's call our second number: \(10\mathrm{c} + \mathrm{d}\) (where 'c' is the tens digit and 'd' is the units digit)
After exchanging tens digits:
The original difference is: \(|(10\mathrm{a} + \mathrm{b}) - (10\mathrm{c} + \mathrm{d})| = |10(\mathrm{a} - \mathrm{c}) + (\mathrm{b} - \mathrm{d})|\)
The new difference is: \(|(10\mathrm{c} + \mathrm{b}) - (10\mathrm{a} + \mathrm{d})| = |10(\mathrm{c} - \mathrm{a}) + (\mathrm{b} - \mathrm{d})| = |10(\mathrm{a} - \mathrm{c}) - (\mathrm{b} - \mathrm{d})|\)
We're told that the difference changes by 4. Let's think about this carefully.
Original difference: \(|10(\mathrm{a} - \mathrm{c}) + (\mathrm{b} - \mathrm{d})|\)
New difference: \(|10(\mathrm{a} - \mathrm{c}) - (\mathrm{b} - \mathrm{d})|\)
For the change to be exactly 4, we need:
\(||10(\mathrm{a} - \mathrm{c}) - (\mathrm{b} - \mathrm{d})| - |10(\mathrm{a} - \mathrm{c}) + (\mathrm{b} - \mathrm{d})|| = 4\)
Let's say \(\mathrm{x} = 10(\mathrm{a} - \mathrm{c})\) and \(\mathrm{y} = (\mathrm{b} - \mathrm{d})\). Then we need: \(||\mathrm{x} - \mathrm{y}| - |\mathrm{x} + \mathrm{y}|| = 4\)
This equation is satisfied when either:
Therefore: \(\mathrm{b} - \mathrm{d} = ±2\), which means \(|\mathrm{b} - \mathrm{d}| = 2\)
Process Skill: MANIPULATE - Working with absolute value expressions to derive the key constraint
Now we know that the units digits must differ by exactly 2. To maximize the original difference \(|10(\mathrm{a} - \mathrm{c}) + (\mathrm{b} - \mathrm{d})|\), we want to make both terms as large as possible and have them work together.
For maximum difference:
Let's choose \(\mathrm{a} = 9, \mathrm{c} = 1\), so \(10(\mathrm{a} - \mathrm{c}) = 80\)
Let's choose \(\mathrm{b} = 9, \mathrm{d} = 7\), so \((\mathrm{b} - \mathrm{d}) = 2\)
This gives us:
Let's verify: After swapping tens digits:
Process Skill: APPLY CONSTRAINTS - Using our derived constraint to find the maximum while satisfying all conditions
The greatest possible difference between the original pair of integers is 82.
This corresponds to answer choice C) 82.
Students often confuse this constraint with "the new difference equals 4" or "the original difference equals 4." The key insight is that we need |new difference - original difference| = 4, not that either difference itself equals 4. This misinterpretation leads to setting up completely wrong equations.
When exchanging tens digits, students may incorrectly think both numbers get the same tens digit, rather than understanding that the tens digits are swapped between the two numbers. For example, if we have 35 and 72, after exchange we get 75 and 32 (swapping the 3 and 7), not 75 and 75 or some other incorrect combination.
Students may forget that tens digits of 2-digit numbers must be between 1 and 9 (not 0), while units digits can be 0-9. This oversight can lead to invalid number combinations when trying to maximize the difference.
When working with \(||10(\mathrm{a}-\mathrm{c}) - (\mathrm{b}-\mathrm{d})| - |10(\mathrm{a}-\mathrm{c}) + (\mathrm{b}-\mathrm{d})|| = 4\), students often struggle with the nested absolute values and may incorrectly conclude that any relationship between the terms works, missing that we specifically need \(|\mathrm{b}-\mathrm{d}| = 2\).
Even after correctly finding that \(|\mathrm{b}-\mathrm{d}| = 2\), students may choose digit combinations where the terms \(10(\mathrm{a}-\mathrm{c})\) and \((\mathrm{b}-\mathrm{d})\) work against each other rather than together. For maximum difference, we want both terms to have the same sign and add up, not subtract.
Students may find a large difference but forget to check that their chosen numbers actually satisfy the "difference changes by 4" condition. This verification step is crucial because not all combinations that seem to maximize will actually satisfy the constraint.
Students might calculate a difference like 90 (from 91 and 1) that seems maximum but doesn't satisfy the "changes by 4" constraint, and select this incorrect maximum instead of the constrained maximum of 82.