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Consider all positive integers \(\mathrm{a}\), \(\mathrm{b}\), and \(\mathrm{c}\) such that \(135\) is a factor of each of the expressions \(15\mathrm{a}\), \(25\mathrm{b}\) and \(30\mathrm{c}\). What is the greatest common factor of all possible sums \(\mathrm{a} + \mathrm{b} + \mathrm{c}\) ?
Let's break down what this problem is asking in plain English. We have three expressions: \(15\mathrm{a}\), \(25\mathrm{b}\), and \(30\mathrm{c}\), where a, b, and c are positive integers. The problem tells us that 135 must be a factor of each of these expressions.
What does it mean for 135 to be a factor? It means that when we divide \(15\mathrm{a}\) by 135, we get a whole number. Same for \(25\mathrm{b} \div 135\) and \(30\mathrm{c} \div 135\).
Our goal is to find all possible values of a, b, and c that make this work, then look at all the possible sums \(\mathrm{a} + \mathrm{b} + \mathrm{c}\), and finally find what number divides ALL of these sums.
Process Skill: TRANSLATE - Converting the factor relationship into clear mathematical requirements
To understand when 135 divides our expressions, let's first break down 135 into its basic building blocks (prime factors):
\(135 = 27 \times 5 = 3^3 \times 5^1\)
Now let's look at each expression:
This tells us what a, b, and c must contain as factors.
Process Skill: INFER - Drawing conclusions about the required prime factor composition
Let's figure out the smallest possible values for a, b, and c:
For \(15\mathrm{a}\) to be divisible by 135:
For \(25\mathrm{b}\) to be divisible by 135:
For \(30\mathrm{c}\) to be divisible by 135:
Let's verify: \(15(9) = 135\) ✓, \(25(27) = 675 = 135 \times 5\) ✓, \(30(9) = 270 = 135 \times 2\) ✓
Now that we know the minimum values, what about all other possible values?
Since we need:
Therefore, any valid sum \(\mathrm{a} + \mathrm{b} + \mathrm{c}\) has the form:
\(\mathrm{a} + \mathrm{b} + \mathrm{c} = 9\mathrm{k} + 27\mathrm{m} + 9\mathrm{n} = 9(\mathrm{k} + 3\mathrm{m} + \mathrm{n})\)
Since k, m, and n can be any positive integers, \((\mathrm{k} + 3\mathrm{m} + \mathrm{n})\) can be any integer ≥ 5 (when k=1, m=1, n=1).
Every possible sum \(\mathrm{a} + \mathrm{b} + \mathrm{c}\) can be written as 9 times some integer that's at least 5.
The possible sums are: \(9 \times 5, 9 \times 6, 9 \times 7, 9 \times 8, 9 \times 9, 9 \times 10, ...\)
Which gives us: 45, 54, 63, 72, 81, 90, ...
What's the greatest number that divides ALL of these values? Since each one is 9 times an integer, and we can get consecutive integers starting from 5, the only common factor is 9.
To confirm: \(\mathrm{GCD}(45, 54, 63, 72, 81, ...) = 9\)
The greatest common factor of all possible sums \(\mathrm{a} + \mathrm{b} + \mathrm{c}\) is 9.
The answer is C.
Students may confuse the phrase "135 is a factor of \(15\mathrm{a}\)" and think it means \(15\mathrm{a} = 135\), leading them to solve \(\mathrm{a} = 9\) as the only solution rather than understanding that \(15\mathrm{a}\) must be a multiple of 135. This fundamental misunderstanding would completely derail their approach from the start.
2. Focusing on finding specific values instead of the general patternStudents might get stuck trying to find all individual possible values of a, b, and c rather than recognizing they need to find the pattern that describes ALL possible values. They may list out a few cases like (9,27,9), (18,27,9), etc., but miss the systematic approach of expressing these as multiples.
3. Misunderstanding what "greatest common factor of all possible sums" meansStudents may interpret this as finding the GCD of just a few example sums rather than understanding they need to find what divides EVERY possible sum \(\mathrm{a} + \mathrm{b} + \mathrm{c}\). This leads them to calculate GCD of specific cases like \(\mathrm{GCD}(45, 54, 63)\) instead of recognizing the infinite set of all possible sums.
Students may make errors when breaking down \(135 = 3^3 \times 5^1\) or when analyzing what additional factors a, b, and c need to provide. For example, they might incorrectly conclude that a needs \(3^3\) instead of \(3^2\) as a factor, leading to wrong minimum values.
2. Arithmetic errors in finding minimum valuesWhen calculating the minimum values, students might make computational mistakes. For instance, they might calculate that b needs to provide \(3^3 = 27\) but then incorrectly conclude the minimum value is something other than 27, or make errors in verification steps.
3. Incorrect algebraic manipulation when expressing the general formStudents may struggle with correctly expressing \(\mathrm{a} + \mathrm{b} + \mathrm{c} = 9\mathrm{k} + 27\mathrm{m} + 9\mathrm{n} = 9(\mathrm{k} + 3\mathrm{m} + \mathrm{n})\). They might factor incorrectly or fail to recognize that this means every sum is a multiple of 9.
Students might calculate the minimum possible sum (which is 45) and mistakenly select an answer choice that represents this value or a factor of it, rather than recognizing that 9 is the greatest common divisor of ALL possible sums.
2. Choosing a factor of the correct answerAfter correctly determining that all sums are multiples of 9, students might select 3 (choice A) thinking that since 3 divides 9, it's also a common factor, without recognizing that 9 is the GREATEST common factor.