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A certain airline's fleet consisted of \(\mathrm{60}\) Type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired \(\mathrm{3}\) of the Type A planes and acquired \(\mathrm{4}\) new Type B planes. How many years did it take before the number of Type A planes left in the airline's fleet was less than \(\mathrm{50}\%\) of the fleet?
Let's understand what's happening in plain English: We have an airline that starts with 60 Type A planes at the beginning of 1980. Every year, they make the same changes - they get rid of 3 Type A planes (retirement) and they buy 4 new Type B planes. We want to know how many years it takes until the Type A planes make up less than half of all the planes they own.
To be very clear about what "less than 50 percent" means: if Type A planes are exactly 50% of the fleet, that's NOT what we want - we need them to be LESS than 50%. So if the total fleet has 100 planes, we need fewer than 50 Type A planes.
Process Skill: TRANSLATE
Let's figure out how to calculate what happens each year. We'll use simple patterns:
After n years:
- Type A planes = \(60 - 3\mathrm{n}\) (we started with 60 and lose 3 each year)
- Type B planes = \(4\mathrm{n}\) (we started with 0 and gain 4 each year)
- Total fleet = Type A + Type B = \((60 - 3\mathrm{n}) + 4\mathrm{n} = 60 + \mathrm{n}\)
This makes sense: each year we lose 3 planes but gain 4 planes, so our total fleet grows by 1 plane per year.
We want Type A planes to be less than 50% of the total fleet. In mathematical terms:
Type A planes < 50% of total fleet
\(60 - 3\mathrm{n} < 0.5 \times (60 + \mathrm{n})\)
\(60 - 3\mathrm{n} < 30 + 0.5\mathrm{n}\)
\(60 - 30 < 3\mathrm{n} + 0.5\mathrm{n}\)
\(30 < 3.5\mathrm{n}\)
\(\mathrm{n} > 30/3.5 = 60/7 \approx 8.57\)
Since n must be a whole number of years, we need n ≥ 9 years.
Process Skill: INFER
Let's verify our answer by tracking the actual numbers year by year:
Year 0 (beginning of 1980): 60 Type A, 0 Type B, Total = 60
Type A percentage = \(60/60 = 100\%\)
Year 1 (end of 1980): 57 Type A, 4 Type B, Total = 61
Type A percentage = \(57/61 \approx 93.4\%\)
Year 6: 42 Type A, 24 Type B, Total = 66
Type A percentage = \(42/66 \approx 63.6\%\)
Year 7: 39 Type A, 28 Type B, Total = 67
Type A percentage = \(39/67 \approx 58.2\%\)
Year 8: 36 Type A, 32 Type B, Total = 68
Type A percentage = \(36/68 \approx 52.9\%\)
Year 9: 33 Type A, 36 Type B, Total = 69
Type A percentage = \(33/69 \approx 47.8\%\)
At year 9, Type A planes make up about 47.8% of the fleet, which is less than 50% for the first time.
The answer is D. 9 years.
At the end of the 9th year, Type A planes represent approximately 47.8% of the total fleet, which is the first time they drop below 50% of the total fleet.
Students often confuse "less than 50%" with "less than or equal to 50%" or "at most 50%". They might think that exactly 50% satisfies the condition, when the problem specifically asks for the first time Type A planes become LESS than half the fleet. This leads to selecting an answer that's one year too early.
The problem states the fleet "consisted of 60 Type A planes at the beginning of 1980" and changes happen "at the end of each year, starting with 1980". Students may get confused about whether to count from the beginning or end of 1980, or may miscount the years by starting from year 1 instead of year 0.
Some students struggle to correctly model how the fleet changes each year. They might incorrectly account for the retirement and acquisition, such as thinking both Type A retirement and Type B acquisition affect the Type A count, or forgetting that the total fleet size changes each year.
When solving \(60 - 3\mathrm{n} < 0.5(60 + \mathrm{n})\), students commonly make errors like: incorrectly distributing 0.5, making sign errors when moving terms across the inequality, or miscalculating \(30/3.5 = 60/7 \approx 8.57\).
If using the verification approach, students may make simple arithmetic errors when calculating the number of planes each year (60-3n for Type A, 4n for Type B) or when computing percentages (like calculating \(33/69\) incorrectly).
After finding n > 8.57, students might incorrectly conclude that n = 8 is sufficient, forgetting that since we need n to be greater than 8.57, we must round UP to n = 9 years.
Students correctly find n > 8.57 but select 8 instead of 9, either because they round down instead of up, or because they think "more than 8 and a bit" means 8 is close enough.
Even after correct calculations, students might select the year when Type A planes are closest to 50% rather than the first year they drop below 50%, leading to selecting year 8 (where Type A is about 52.9%) instead of year 9 (where Type A is about 47.8%).