e-GMAT Logo
NEUR
N

The straight-line distance between Town A and Town B is 15 km. Most travelers passing through the towns, however, use...

GMAT Two Part Analysis : (TPA) Questions

Source: Mock
Two Part Analysis
Quant - Fitting Values
HARD
...
...
Notes
Post a Query

The straight-line distance between Town A and Town B is 15 km. Most travelers passing through the towns, however, use two highways—first traveling \(\mathrm{x}\) km west from Town A on one highway and then traveling \(\mathrm{y}\) km north to Town B on a different highway. The intersection of these highways is farther from Town A than Town B.

Select values for \(\mathrm{x}\) and for \(\mathrm{y}\) that are jointly consistent with the given information. Make only two selections, one in each column.

x

y

5

8

9

10

12

Solution

Phase 1: Owning the Dataset

Visualization Selection

This is a geometry problem involving distances and paths, so let's draw a diagram showing the towns and highways.

Visual Representation

        Town B
         |
         | y km (north)
         |
Town A---●---Intersection
    x km (west)
    
    Straight-line: 15 km

The travelers go from Town A west to an intersection, then north to Town B. The straight-line distance from A to B is 15 km.

Phase 2: Understanding the Question

Key Relationships

  1. Right Triangle Formation: The path forms a right triangle where:
    • One leg = x km (horizontal distance west)
    • Other leg = y km (vertical distance north)
    • Hypotenuse = 15 km (straight-line distance)
  2. Pythagorean Theorem: \(\mathrm{x}^2 + \mathrm{y}^2 = 15^2 = 225\)
  3. Distance Constraint: "The intersection is farther from Town A than Town B"
    • Distance from A to intersection = x
    • Distance from B to intersection = y
    • Therefore: \(\mathrm{x} > \mathrm{y}\)

What We're Looking For

We need values of x and y from the choices [5, 8, 9, 10, 12] that:

  • Satisfy \(\mathrm{x}^2 + \mathrm{y}^2 = 225\)
  • Meet the condition \(\mathrm{x} > \mathrm{y}\)

Phase 3: Finding the Answer

Systematic Check

Let's check which combinations work:

If x = 12:

  • \(12^2 + \mathrm{y}^2 = 225\)
  • \(144 + \mathrm{y}^2 = 225\)
  • \(\mathrm{y}^2 = 81\)
  • \(\mathrm{y} = 9\)

Does this satisfy \(\mathrm{x} > \mathrm{y}\)? Yes: \(12 > 9\)

Verification (use calculator if needed):

  • \(12^2 + 9^2 = 144 + 81 = 225\)
  • This equals \(15^2\)

? Stop here - we found our answer.

Phase 4: Solution

Final Answer

  • x = 12 (distance west from Town A to intersection)
  • y = 9 (distance north from intersection to Town B)

These values satisfy both requirements:

  1. They form a right triangle with hypotenuse 15 km (\(12^2 + 9^2 = 225 = 15^2\))
  2. The intersection is farther from Town A than Town B (\(12 > 9\))
Rate this Solution
Tell us what you think about this solution
...
...
Forum Discussions
Start a new discussion
Post
Load More
Similar Questions
Finding similar questions...
Previous Attempts
Loading attempts...
Similar Questions
Finding similar questions...
Parallel Question Generator
Create AI-generated questions with similar patterns to master this question type.