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The Quasi JX is a new car model. Under ideal driving conditions, the Quasi Jx's fuel economy is \(\mathrm{E}\) kilometers per liter (\(\mathrm{E \, km/L}\)) when its driving speed is constant at \(\mathrm{S}\) kilometers per hour (\(\mathrm{S \, km/h}\)).
In terms of the variables \(\mathrm{S}\) and \(\mathrm{E}\), select the expression that represents the number of liters of fuel used in 1 hour of driving under ideal driving conditions at a constant speed \(\mathrm{S}\), and select the expression that represents the number of liters of fuel used in a 60 km drive under ideal driving conditions at a constant speed \(\mathrm{S}\).
\(\frac{\mathrm{S}}{\mathrm{E}}\)
\(\frac{\mathrm{E}}{\mathrm{S}}\)
\(\frac{60}{\mathrm{E}}\)
\(\frac{60}{\mathrm{S}}\)
\(\frac{\mathrm{S}}{60}\)
\(\frac{\mathrm{E}}{60}\)
Let's pick specific values to understand the relationships:
Since we're dealing with rates and relationships, let's create a simple rate diagram:
Fuel Economy: E km/L → Car travels E kilometers using 1 liter Speed: S km/h → Car travels S kilometers in 1 hour Key Relationship: Distance = Fuel Economy × Fuel Used Fuel Used = Distance ÷ Fuel Economy
Statement 1: Liters of fuel in 1 hour
Statement 2: Liters of fuel in 60 km
The fundamental formula is: Fuel Used = Distance Traveled ÷ Fuel Economy
For Statement 1 (Liters in 1 hour):
Verifying with our example: \(\mathrm{100\,km ÷ 20\,km/L = 5\,liters}\) ✓
For Statement 2 (Liters in 60 km):
Verifying with our example: \(\mathrm{60\,km ÷ 20\,km/L = 3\,liters}\) ✓
Both answers follow directly from the relationship: when fuel economy is E km/L, the fuel needed equals distance divided by E.