The graph indicates, for each of the years 1993, 1998, and 2003, the percent of the total number of tourists...

Owning The Dataset

Table 1: Text Analysis

Table 2: Chart Analysis

Key Insights

In 1993, tourism on Island X was heavily focused on 14-day package stays, with half of all tourists staying exactly 14 days. Over the following decade, 14-day stays declined in popularity, while 7-day stays became more common, overtaking 14-day stays as the most frequent length by 2003. The combined percentage of tourists staying either 7 or 14 days was highest in 1993 (63%), and this figure fell sharply to 41% in 1998 and 35% in 2003, indicating a diversification in how long visitors chose to stay on the island.

Step-by-Step Solution

Question 1: Identifying the Year with Highest Combined Probability

Complete Statement:

The combined probability that a tourist chosen at random had stayed either 7 or 14 days on the island was highest in ____

Breaking Down the Statement

• Statement Breakdown 1:
  • Key Phrase: combined probability
    • Meaning: The sum of probabilities for two different stay durations.
    • Relation to Chart: Obtain the percentages for tourists who stayed 7 days and 14 days from the graph for each year.
    • Important Implications: We need to add these specific values together for each year and then compare the totals.
• Statement Breakdown 2:
  • Key Phrase: either 7 or 14 days
    • Meaning: Only the groups of tourists staying exactly 7 days or exactly 14 days are counted.
    • Relation to Chart: Locate the corresponding bars or points for 7 and 14 days for each year.
    • Important Implications: No other durations should be included when calculating the combined probability.
• What is needed: Which year (1993, 1998, or 2003) had the highest total probability for a tourist staying either 7 or 14 days.

Solution:

• Condensed Solution Implementation:
  For each year, sum the percentages for tourists who stayed 7 days and 14 days; then compare the sums.
• Necessary Data points:
  Percentages for 7-day and 14-day stays for all three years: 1993: 13% (7-day), 50% (14-day); 1998: 16% (7-day), 25% (14-day); 2003: 21% (7-day), 14% (14-day).
  • Calculations Estimations:
    For 1993: \(13\% + 50\% = 63\%\); for 1998: \(16\% + 25\% = 41\%\); for 2003: \(21\% + 14\% = 35\%\).
  • Comparison to Answer Choices:
    63% (1993) is higher than 41% (1998) and 35% (2003), so 1993 is the answer.

FINAL ANSWER Blank 1: 1993

Question 2: Calculating the Combined Probability Value

Complete Statement:

and, to the nearest tenth, that probability was ____

Breaking Down the Statement

• Statement Breakdown 1:
  • Key Phrase: that probability
    • Meaning: Refers to the combined 7-day and 14-day probability found for the year from blank 1.
    • Relation to Chart: From previous calculation, this is 63% for 1993.
• Statement Breakdown 2:
  • Key Phrase: to the nearest tenth
    • Meaning: The probability must be expressed as a decimal rounded to one decimal place.
    • Relation to Chart: Convert 63% to 0.63 and then round to the nearest tenth.
• What is needed: The decimal value of 63%, rounded to one decimal place.

Solution:

• Condensed Solution Implementation:
  Convert 63% to a decimal probability by dividing by 100, then round to one decimal place.
• Necessary Data points:
  Combined probability for 1993 is 63%.
  • Calculations Estimations:
    \(63\% = 0.63\). When rounded to the nearest tenth, 0.63 becomes 0.6.
  • Comparison to Answer Choices:
    Of the choices (0.1, 0.2, 0.4, 0.6), 0.6 is correct.

FINAL ANSWER Blank 2: 0.6

Summary

Summing the percentages for tourists staying 7 and 14 days for each year, we find that 1993 (63%) stands out well above the other years. Converting this value to a decimal and rounding gives 0.6.

Question Independence Analysis

The two blanks are dependent. The answer to the second blank (the probability) relies on which year was selected in the first blank, since the probability value changes depending on the year chosen.