The daily profit, P, for selling x units of a certain item at a sporting goods store can be modeled...
GMAT Data Sufficiency : (DS) Questions
The daily profit, P, for selling x units of a certain item at a sporting goods store can be modeled by the function \(\mathrm{P(x)} = -\mathrm{a}(\mathrm{x} - \frac{\mathrm{b}}{2\mathrm{a}})^2 + \frac{\mathrm{b}^2}{4\mathrm{a}} + \mathrm{c}\), where a and b are positive constants and c is a nonnegative constant. What is the maximum daily profit for selling this item?
- \(\mathrm{b}^2 + 4\mathrm{ac} = \frac{52\mathrm{ac}}{3}\)
- \(\mathrm{c} = 360\)
Understanding the Question
We need to find the maximum daily profit for selling a certain item. The profit function is given as:
\(\mathrm{P(x)} = -\mathrm{a}(\mathrm{x} - \mathrm{b}/2\mathrm{a})^2 + \mathrm{b}^2/4\mathrm{a} + \mathrm{c}\)
where:
- a and b are positive constants
- c is a nonnegative constant
- x represents units sold
Key Insight - Recognizing Vertex Form
This profit function is already in vertex form - a huge time-saver! Since a > 0, the coefficient -a is negative, making this a downward-opening parabola.
For any parabola in vertex form \(\mathrm{P(x)} = -\mathrm{a}(\mathrm{x} - \mathrm{h})^2 + \mathrm{k}\):
- The vertex (maximum point) occurs at \(\mathrm{x} = \mathrm{h}\)
- The maximum value equals k
In our case:
- Maximum occurs at \(\mathrm{x} = \mathrm{b}/2\mathrm{a}\)
- Maximum profit = \(\mathrm{b}^2/4\mathrm{a} + \mathrm{c}\)
Therefore, to find the specific numerical value of the maximum profit, we need to determine \(\mathrm{b}^2/4\mathrm{a} + \mathrm{c}\).
Analyzing Statement 1
Statement 1: \(\mathrm{b}^2 + 4\mathrm{ac} = 52\mathrm{ac}/3\)
Let's see if this alone gives us a specific maximum profit value.
Starting with the given equation:
- \(\mathrm{b}^2 + 4\mathrm{ac} = 52\mathrm{ac}/3\)
- \(\mathrm{b}^2 = 52\mathrm{ac}/3 - 4\mathrm{ac}\)
- \(\mathrm{b}^2 = 52\mathrm{ac}/3 - 12\mathrm{ac}/3\)
- \(\mathrm{b}^2 = 40\mathrm{ac}/3\)
Now we can find \(\mathrm{b}^2/4\mathrm{a}\):
- \(\mathrm{b}^2/4\mathrm{a} = (40\mathrm{ac}/3) ÷ 4\mathrm{a} = 40\mathrm{c}/12 = 10\mathrm{c}/3\)
So the maximum profit becomes:
- Maximum profit = \(\mathrm{b}^2/4\mathrm{a} + \mathrm{c} = 10\mathrm{c}/3 + \mathrm{c} = 10\mathrm{c}/3 + 3\mathrm{c}/3 = \)\(13\mathrm{c}/3\)
This tells us the maximum profit equals \(13\mathrm{c}/3\), but without knowing the specific value of c, we cannot determine a numerical answer for the maximum profit.
Statement 1 alone is NOT sufficient. ❌
This eliminates choices A and D.
Analyzing Statement 2
Now let's forget Statement 1 completely and analyze Statement 2 independently.
Statement 2: \(\mathrm{c} = 360\)
With only this information:
- Maximum profit = \(\mathrm{b}^2/4\mathrm{a} + \mathrm{c} = \mathrm{b}^2/4\mathrm{a} + 360\)
We know \(\mathrm{c} = 360\), but we still don't know the values of a and b (and therefore cannot determine \(\mathrm{b}^2/4\mathrm{a}\)). Without this crucial piece, we cannot calculate the specific maximum profit value.
Statement 2 alone is NOT sufficient. ❌
This eliminates choice B.
Combining Both Statements
Now let's see what happens when we use both statements together.
From Statement 1, we derived: \(\mathrm{b}^2/4\mathrm{a} = 10\mathrm{c}/3\)
From Statement 2: \(\mathrm{c} = 360\)
Substituting \(\mathrm{c} = 360\) into our expression from Statement 1:
- \(\mathrm{b}^2/4\mathrm{a} = 10(360)/3 = 3600/3 = 1200\)
Therefore:
- Maximum profit = \(\mathrm{b}^2/4\mathrm{a} + \mathrm{c} = 1200 + 360 = \)1560
With both statements together, we can determine a unique, specific value for the maximum profit: $1560.
Both statements together ARE sufficient. ✓
[STOP - Sufficient!]
This eliminates choice E.
The Answer: C
Since neither statement alone is sufficient, but together they provide enough information to find the exact maximum profit, the answer is C.
Answer Choice C: "Both statements together are sufficient, but neither statement alone is sufficient."