Quick Sell Outlet sold a total of 40 televisions, each of which was either a Model P television or a...
GMAT Data Sufficiency : (DS) Questions
Quick Sell Outlet sold a total of 40 televisions, each of which was either a Model P television or a Model Q television. Each Model P television sold for \(\mathrm{\$p}\) and each Model Q sold for \(\mathrm{\$q}\). The average (arithmetic mean) selling price of the 40 televisions was \(\mathrm{\$141}\). How many of the 40 televisions were Model P televisions?
- the Model P televisions sold for \(\mathrm{\$30}\) less than the Model Q televisions
- Either \(\mathrm{p = 120}\) or \(\mathrm{q = 120}\)
Understanding the Question
We need to find: How many of the 40 televisions were Model P televisions?
Given Information
- Total televisions sold: 40
- Each TV is either Model P (sold for \(\$\mathrm{p}\)) or Model Q (sold for \(\$\mathrm{q}\))
- Average selling price of all 40 TVs: \(\$141\)
What We Need to Determine
For sufficiency, we need enough information to find the exact number of Model P televisions sold. This is a value question - we need a specific number, not just yes/no.
Key Insight
This is a weighted average problem. The \(\$141\) average must lie between the two prices p and q. The key insight is that we can use "balance point" reasoning: if the average is closer to one price, more of that model was sold. Different price combinations could potentially give us different quantity mixes.
Analyzing Statement 1
Statement 1: The Model P televisions sold for $30 less than the Model Q televisions
This tells us that \(\mathrm{p} = \mathrm{q} - 30\), establishing a fixed \(\$30\) difference between the two prices.
Testing Different Scenarios
Let's test whether different price levels could give us different quantity mixes:
Scenario A: If \(\mathrm{q} = \$150\), then \(\mathrm{p} = \$120\)
- The average \(\$141\) is \(\$21\) above p and \(\$9\) below q
- Since \(\$141\) is much closer to \(\$150\) than to \(\$120\), more Model Q TVs must have been sold
Scenario B: If \(\mathrm{q} = \$180\), then \(\mathrm{p} = \$150\)
- The average \(\$141\) is now \(\$9\) below p and \(\$39\) below q
- Since \(\$141\) is closer to \(\$150\) than to \(\$180\), more Model P TVs must have been sold
Conclusion
Different price levels lead to different quantity mixes. Without knowing the actual prices, we cannot determine a unique answer for how many Model P televisions were sold.
Statement 1 is NOT sufficient.
This eliminates choices A and D.
Analyzing Statement 2
Now let's forget Statement 1 completely and analyze Statement 2 independently.
Statement 2: Either p = 120 or q = 120
This gives us one concrete price, but we still don't know the other price.
Testing Different Scenarios
Case 1: If \(\mathrm{p} = \$120\) (Model P costs \(\$120\))
- We don't know q, but since the average is \(\$141\), q must be greater than \(\$141\)
- If \(\mathrm{q} = \$150\): The \(\$141\) average (closer to \(\$150\)) means more Model Q were sold
- If \(\mathrm{q} = \$200\): The \(\$141\) average (closer to \(\$120\)) means more Model P were sold
- Different values of q give different quantity mixes
Case 2: If \(\mathrm{q} = \$120\) (Model Q costs \(\$120\))
- This creates an interesting situation: the average is \(\$141\), which is above \(\mathrm{q} = \$120\)
- For the average to be higher than \(\$120\), p must be greater than \(\$141\)
- But wait - this means the cheaper Model Q costs \(\$120\) and the more expensive Model P costs over \(\$141\)
- Different values of p (say \(\$160\) or \(\$180\)) would still give different mixes
Conclusion
Knowing just one price doesn't uniquely determine the quantity mix.
Statement 2 is NOT sufficient.
This eliminates choice B.
Combining Statements
Let's see what happens when we use both statements together.
From Statement 1: \(\mathrm{p} = \mathrm{q} - 30\) (Model P costs \(\$30\) less)
From Statement 2: Either p = 120 or q = 120
Combined Analysis
Case 1: If \(\mathrm{p} = \$120\)
- Using Statement 1: \(\mathrm{q} = \mathrm{p} + 30 = \$120 + \$30 = \$150\)
- We now have concrete prices: \(\mathrm{p} = \$120\) and \(\mathrm{q} = \$150\)
- With these specific prices and the \(\$141\) average, we can determine the exact mix
Let's verify this makes sense:
- Average \(\$141\) is \(\$21\) above \(\$120\) and \(\$9\) below \(\$150\)
- Since \(\$141\) is closer to \(\$150\), more Model Q televisions were sold
- The exact calculation would show: 12 Model P and 28 Model Q televisions
[STOP - Sufficient!]
But let's check the other case to be thorough:
Case 2: If \(\mathrm{q} = \$120\)
- Using Statement 1: \(\mathrm{p} = \mathrm{q} - 30 = \$120 - \$30 = \$90\)
- This gives us prices: \(\mathrm{p} = \$90\) and \(\mathrm{q} = \$120\)
- But notice: Both prices (\(\$90\) and \(\$120\)) are BELOW the average (\(\$141\))
- This is mathematically impossible! A weighted average cannot exceed both component values
Why Together They Are Sufficient
Only Case 1 is valid, giving us unique prices of \(\mathrm{p} = \$120\) and \(\mathrm{q} = \$150\). With these specific prices and the known average of \(\$141\), we can determine exactly how many Model P televisions were sold.
The statements together are sufficient.
This eliminates choice E.
The Answer: C
Both statements together provide unique values for p and q, allowing us to determine the exact number of Model P televisions sold. Neither statement alone is sufficient.
Answer Choice C: "Both statements together are sufficient, but neither statement alone is sufficient."