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Is x > 1? \((\mathrm{x} + 1)(|\mathrm{x}| - 1) > 0\) \(|\mathrm{x}|...

GMAT Data Sufficiency : (DS) Questions

Source: Official Guide
Data Sufficiency
DS-Basics
HARD
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Notes
Post a Query

Is \(\mathrm{x} > 1\)?

  1. \((\mathrm{x} + 1)(|\mathrm{x}| - 1) > 0\)
  2. \(|\mathrm{x}| < 5\)
A
Statement (1) ALONE is sufficient but statement (2) ALONE is not sufficient.
B
Statement (2) ALONE is sufficient but statement (1) ALONE is not sufficient.
C
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D
EACH statement ALONE is sufficient.
E
Statements (1) and (2) TOGETHER are not sufficient.
Solution

Understanding the Question

We need to determine: Is \(\mathrm{x > 1}\)?

This is a yes/no question. To be sufficient, a statement must allow us to definitively answer either "yes, x is always greater than 1" or "no, x is not always greater than 1" (meaning \(\mathrm{x ≤ 1}\) for at least some values).

Given Information: No constraints are provided in the question itself.

Key Insight: Since we're dealing with inequalities involving absolute values, we should focus on where the expressions change sign rather than testing every possible region.

Analyzing Statement 1

Statement 1: \(\mathrm{(x + 1)(|x| - 1) > 0}\)

For a product to be positive, both factors must have the same sign (both positive or both negative).

Let's identify the critical points where each factor changes sign:

- \(\mathrm{(x + 1) = 0}\) when \(\mathrm{x = -1}\)

- Negative when \(\mathrm{x < -1}\)

- Positive when \(\mathrm{x > -1}\)

- \(\mathrm{|x| - 1 = 0}\) when \(\mathrm{|x| = 1}\), which means \(\mathrm{x = -1}\) or \(\mathrm{x = 1}\)

- When \(\mathrm{-1 < x < 1}\): \(\mathrm{|x| < 1}\), so \(\mathrm{|x| - 1 < 0}\) (negative)

- When \(\mathrm{x < -1}\) or \(\mathrm{x > 1}\): \(\mathrm{|x| > 1}\), so \(\mathrm{|x| - 1 > 0}\) (positive)

Finding When Both Factors Have the Same Sign

Case 1: Both factors positive

- Need \(\mathrm{x + 1 > 0}\)\(\mathrm{x > -1}\)

- Need \(\mathrm{|x| - 1 > 0}\)\(\mathrm{x < -1}\) or \(\mathrm{x > 1}\)

- The overlap: Only when \(\mathrm{x > 1}\)

Case 2: Both factors negative

- Need \(\mathrm{x + 1 < 0}\)\(\mathrm{x < -1}\)

- Need \(\mathrm{|x| - 1 < 0}\)\(\mathrm{-1 < x < 1}\)

- No overlap exists! These conditions contradict each other.

Therefore, \(\mathrm{(x + 1)(|x| - 1) > 0}\) holds only when \(\mathrm{x > 1}\).

Since Statement 1 forces \(\mathrm{x > 1}\), we can definitively answer "yes" to our question.

[STOP - Statement 1 is Sufficient!]

This eliminates choices B, C, and E.

Analyzing Statement 2

Now we analyze Statement 2 independently, forgetting Statement 1 completely.

Statement 2: \(\mathrm{|x| < 5}\)

This means \(\mathrm{-5 < x < 5}\).

Within this range, x could be:

- \(\mathrm{x = 0}\) → Is \(\mathrm{0 > 1}\)? No

- \(\mathrm{x = 2}\) → Is \(\mathrm{2 > 1}\)? Yes

Since we get different answers ("no" for \(\mathrm{x = 0}\), "yes" for \(\mathrm{x = 2}\)), we cannot definitively determine whether \(\mathrm{x > 1}\).

Statement 2 is NOT sufficient.

This eliminates choices B and D.

The Answer: A

- Statement 1 alone: Forces \(\mathrm{x > 1}\) → Can answer "yes" → SUFFICIENT

- Statement 2 alone: Allows both \(\mathrm{x ≤ 1}\) and \(\mathrm{x > 1}\) → Cannot answer definitively → NOT SUFFICIENT

Answer Choice A: "Statement 1 alone is sufficient, but Statement 2 alone is not sufficient."

Answer Choices Explained
A
Statement (1) ALONE is sufficient but statement (2) ALONE is not sufficient.
B
Statement (2) ALONE is sufficient but statement (1) ALONE is not sufficient.
C
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D
EACH statement ALONE is sufficient.
E
Statements (1) and (2) TOGETHER are not sufficient.
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