In four years, Ramona's age in years will be twice Charlie's age in years.
GMAT Two Part Analysis : (TPA) Questions
In four years, Ramona's age in years will be twice Charlie's age in years.
In the table, select values that, according to the given information, could be Ramona's and Charlie's present ages in years. Make only two selections, one in each column.
Phase 1: Owning the Dataset
Understanding the Age Relationship
Let's use a timeline to visualize the ages:
Now In 4 years Charlie: C ----------> C + 4 Ramona: R ----------> R + 4 = 2(C + 4)
Setting Up the Mathematical Relationship
From the given information:
- In 4 years: Ramona's age = 2 × Charlie's age
- Mathematical expression: \(\mathrm{R + 4 = 2(C + 4)}\)
Let's simplify this:
- \(\mathrm{R + 4 = 2C + 8}\)
- \(\mathrm{R = 2C + 4}\)
Key insight: Ramona is currently 4 years older than twice Charlie's age.
Phase 2: Understanding the Question
We need to find:
- Statement 1 (Ramona): A value that could be Ramona's current age
- Statement 2 (Charlie): A value that could be Charlie's current age
Available choices: 2, 12, 14, 20, 24, 28
Phase 3: Finding the Answer
Systematic Checking Strategy
Since we have the relationship \(\mathrm{R = 2C + 4}\), let's check each possible value for Charlie to see if the corresponding Ramona value exists in our choices.
If Charlie = 2:
- Ramona = \(\mathrm{2(2) + 4 = 8}\)
- Is 8 in our choices? No, continue.
If Charlie = 12:
- Ramona = \(\mathrm{2(12) + 4 = 28}\)
- Is 28 in our choices? Yes! ✓
- Stop here - we found our answer.
Verification
Let's verify our answer:
- Current ages: Charlie = 12, Ramona = 28
- In 4 years: Charlie = 16, Ramona = 32
- Is \(\mathrm{32 = 2 × 16}\)? Yes! ✓
Phase 4: Solution
Final Answer:
- Statement 1 (Ramona): 28
- Statement 2 (Charlie): 12
Ramona is currently 28 years old and Charlie is currently 12 years old. In four years, when Charlie is 16, Ramona will be 32, which is exactly twice Charlie's age at that time.