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In a certain factory, five different machines-Machines A through E-produce ceramic figurines, each at different rates. The machines were all brought online at different times, each continuously producing figurines at its own constant rate until 8:00 p.m.:
At 2:45, when Machine E was brought online, the other four machines had produced a total of \(\mathrm{x}\) figurines. After 2:45, the total combined rate of production for all five machines was \(\mathrm{y}\) figurines per hour. Select a value for \(\mathrm{x}\) and a value for \(\mathrm{y}\) so that the above statement accurately reflects the given information. Make only two selections, one in each column.
1750
4300
7525
2800
6250
This is a time-based problem with machines starting at different times, so we'll use a timeline.
1:00 PM 1:15 PM 1:45 PM 2:00 PM 2:45 PM → 8:00 PM | | | | | A starts B starts C starts D starts E starts (1000/hr) (500/hr) (1500/hr) (400/hr) (900/hr)
We need to find:
After 2:45 PM, all five machines run simultaneously, so y is simply the sum of all production rates.
Let's calculate how long each machine runs until 2:45 PM:
Machine A: 1:00 PM to 2:45 PM = 1 hour 45 minutes = 1.75 hours
Machine B: 1:15 PM to 2:45 PM = 1 hour 30 minutes = 1.5 hours
Machine C: 1:45 PM to 2:45 PM = 1 hour
Machine D: 2:00 PM to 2:45 PM = 45 minutes = 0.75 hours
Total x = \(1,750 + 750 + 1,500 + 300 = 4,300\) figurines
After 2:45 PM, all five machines are running:
Total y = \(1,000 + 500 + 1,500 + 400 + 900 = 4,300\) figurines/hour
Both x and y equal 4,300, which is available in our answer choices.
Final Answer: