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How many integers \(\mathrm{n}\) are there such that \(\mathrm{r} < \mathrm{n} < \mathrm{s}\)?
We need to find the exact count of integers n where \(\mathrm{r} < \mathrm{n} < \mathrm{s}\).
This is a value question - we need a specific number as our answer. For this question to be sufficient, we must be able to determine exactly one count of integers between r and s.
The number of integers between two real numbers depends on:
For example, between 1.5 and 4.5 (distance = 3), there are 2 integers (2 and 3). But between 1.9 and 4.9 (also distance = 3), there are 3 integers (2, 3, and 4). Position matters!
Statement 1: \(\mathrm{s} - \mathrm{r} = 5\)
This tells us that s is 5 units greater than r (so r < s), and the exact distance between them is 5. However, it doesn't tell us where they are positioned on the number line.
Let's test different positions to see if we always get the same count:
Test Case 1: \(\mathrm{r} = 1, \mathrm{s} = 6\)
- Integers between 1 and 6: 2, 3, 4, 5
- Count = 4
Test Case 2: \(\mathrm{r} = 1.5, \mathrm{s} = 6.5\)
- Integers between 1.5 and 6.5: 2, 3, 4, 5, 6
- Count = 5
Since different positions give different counts (4 vs 5), we cannot determine a unique answer.
[STOP - Not Sufficient!] Statement 1 alone is NOT sufficient.
This eliminates choices A and D.
Now we forget Statement 1 completely and analyze Statement 2 independently.
Statement 2: r and s are not integers
This eliminates boundary cases where r or s might equal an integer, but tells us nothing about:
Test Case 1: \(\mathrm{r} = 1.5, \mathrm{s} = 2.5\) (both non-integers)
- Integers between them: just 2
- Count = 1
Test Case 2: \(\mathrm{r} = 1.5, \mathrm{s} = 10.5\) (both non-integers)
- Integers between them: 2, 3, 4, 5, 6, 7, 8, 9, 10
- Count = 9
We get completely different counts (1 vs 9), so we cannot determine a unique answer.
[STOP - Not Sufficient!] Statement 2 alone is NOT sufficient.
This eliminates choice B.
Since neither statement alone is sufficient, our answer must be C or E.
With both statements together:
Here's the key insight: When two non-integers are exactly 5 units apart, there are always exactly 5 integers between them!
To understand why, imagine r falls between consecutive integers k and k+1. Since r is not an integer, we can write \(\mathrm{r} = \mathrm{k} + \text{(some fraction between 0 and 1)}\). Then \(\mathrm{s} = \mathrm{r} + 5 = \mathrm{k} + \text{(same fraction)} + 5\).
The integers between r and s must be: k+1, k+2, k+3, k+4, and k+5. That's exactly 5 integers, regardless of where r starts!
Let's verify with concrete examples:
The count is always 5!
[STOP - Sufficient!] Both statements together are sufficient.
This eliminates choice E.
Both statements together give us exactly one answer (5 integers), but neither statement alone is sufficient.
Answer Choice C: "Both statements together are sufficient, but neither statement alone is sufficient."