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Each of the 75 employees at a certain company works in exactly one of the company's 3 departments (Departments X,...

GMAT Two Part Analysis : (TPA) Questions

Source: Mock
Two Part Analysis
Quant - Fitting Values
EASY
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Each of the 75 employees at a certain company works in exactly one of the company's 3 departments (Departments X, Y, and Z). Exactly \(20\%\) of the employees work in Department X, and 10 fewer employees work in Department Y than work in Department Z.

Based on the information provided, select for Department Y and Department Z the numbers of employees who work in Department Y and Department Z. Make only two selections, one in each column.

Department Y
Department Z

15

20

25

30

35

Solution

Phase 1: Owning the Dataset

Visualization Selection

We have a problem about employees distributed across departments. This is best represented with a visual breakdown table showing how the total is partitioned.

Visual Representation


Total Employees: 75

Department X: [***] (20% of 75)
Department Y: [?????] (10 fewer than Z)
Department Z: [???????] (unknown)

Given Information

  • Total employees: 75
  • Exactly 3 departments: X, Y, and Z
  • Each employee works in exactly one department
  • Department X: 20% of employees
  • Department Y: 10 fewer employees than Department Z

Initial Calculations

Department X has: \(20\% \times 75 = 0.20 \times 75 = \mathbf{15}\) employees

Phase 2: Understanding the Question

We need to find the exact number of employees in:

  • Department Y (first selection)
  • Department Z (second selection)

Setting Up the Mathematical Relationships

Let's denote:

  • Department Y has y employees
  • Department Z has z employees

From our given information:

  1. \(\mathrm{y} = \mathrm{z} - 10\) (Y has 10 fewer than Z)
  2. \(15 + \mathrm{y} + \mathrm{z} = 75\) (all employees must sum to 75)

Simplifying equation 2:
\(\mathrm{y} + \mathrm{z} = 60\)

Phase 3: Finding the Answer

Solving the System

We have:

  • \(\mathrm{y} = \mathrm{z} - 10\)
  • \(\mathrm{y} + \mathrm{z} = 60\)

Substituting the first equation into the second:
\((\mathrm{z} - 10) + \mathrm{z} = 60\)
\(2\mathrm{z} - 10 = 60\)
\(2\mathrm{z} = 70\)
\(\mathbf{\mathrm{z} = 35}\)

Therefore:
\(\mathbf{\mathrm{y} = \mathrm{z} - 10 = 35 - 10 = 25}\)

Verification

Let's check our answer:

  • Department X: 15 employees
  • Department Y: 25 employees
  • Department Z: 35 employees
  • Total: \(15 + 25 + 35 = 75\)

Also verifying the constraint: Y has 10 fewer than Z: \(25 = 35 - 10\)

Updated Visual


Total Employees: 75

Department X: [***] 15 employees (20%)
Department Y: [*****] 25 employees
Department Z: [*******] 35 employees

Phase 4: Solution

Final Answer:

  • Department Y: 25
  • Department Z: 35

These values satisfy all our constraints: they sum to 75 total employees (with X's 15), and Department Y has exactly 10 fewer employees than Department Z.

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