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Each of the 75 employees at a certain company works in exactly one of the company's 3 departments (Departments X, Y, and Z). Exactly \(20\%\) of the employees work in Department X, and 10 fewer employees work in Department Y than work in Department Z.
Based on the information provided, select for Department Y and Department Z the numbers of employees who work in Department Y and Department Z. Make only two selections, one in each column.
15
20
25
30
35
We have a problem about employees distributed across departments. This is best represented with a visual breakdown table showing how the total is partitioned.
Total Employees: 75 Department X: [***] (20% of 75) Department Y: [?????] (10 fewer than Z) Department Z: [???????] (unknown)
Department X has: \(20\% \times 75 = 0.20 \times 75 = \mathbf{15}\) employees
We need to find the exact number of employees in:
Let's denote:
From our given information:
Simplifying equation 2:
\(\mathrm{y} + \mathrm{z} = 60\)
We have:
Substituting the first equation into the second:
\((\mathrm{z} - 10) + \mathrm{z} = 60\)
\(2\mathrm{z} - 10 = 60\)
\(2\mathrm{z} = 70\)
\(\mathbf{\mathrm{z} = 35}\)
Therefore:
\(\mathbf{\mathrm{y} = \mathrm{z} - 10 = 35 - 10 = 25}\)
Let's check our answer:
Also verifying the constraint: Y has 10 fewer than Z: \(25 = 35 - 10\) ✓
Total Employees: 75 Department X: [***] 15 employees (20%) Department Y: [*****] 25 employees Department Z: [*******] 35 employees
Final Answer:
These values satisfy all our constraints: they sum to 75 total employees (with X's 15), and Department Y has exactly 10 fewer employees than Department Z.