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An apple farm installed a fish pond on its land to save money and increase potential revenue. Waste apples and...

GMAT Graphics Interpretation : (GI) Questions

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Graphics Interpretation
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Graph showing fertilizer costs and fish sales data

An apple farm installed a fish pond on its land to save money and increase potential revenue. Waste apples and other apple by-products are used to supplement the diet of the fish while the waste from the pond is used to fertilize the apple trees. Fish and apples are both sold for profit. The graph shows the total cost of fertilizer per 10 kg of apples that are sold as well as the total number of fish sold in each year.


Use the drop-down menus to complete the statements in a manner consistent with the given information.

The average amount by which the cost of fertilizer per 10 kg of apples sold decreased from year 1 to year 5 is, to the nearest power of 10, nearest todollars per 10 kg apples per year.
After year 3, the rate of growth in the total number of fish sold per year was
Solution

Owning the Dataset

Table 1: Text Analysis

Text Component Literal Content Simple Interpretation
System setup An apple farm installed a fish pond on its land to save money and increase potential revenue. Apple farm added fish pond to improve finances and expand business.
Resource cycling Waste apples and other apple by-products are used to supplement the diet of the fish while the waste from the pond is used to fertilize the apple trees. Apples feed fish; fish waste fertilizes apple trees—closed-loop sustainability.
Revenue sources Fish and apples are both sold for profit. Both apples and fish contribute to farm income.
Data displayed The graph shows the total cost of fertilizer per 10 kg of apples that are sold as well as the total number of fish sold in each year. Chart tracks fertilizer cost (per 10kg apples) and fish sold each year.

Table 2: Chart Analysis

Chart Component What's Shown What This Tells Us
Chart type Dual-axis line chart over 5 years Compares fertilizer costs and fish sales over time.
X-axis Years 1 to 5 Data covers five yearly intervals.
Left Y-axis Number of fish sold (0 to 3500) Measures fish production output.
Right Y-axis Fertilizer cost per 10 kg apples sold (\(\$0.00 \text{ to } \$0.07\)) Quantifies fertilizer expense for apple sales.
Fish sold trend Dashed line with circle markers, increasing from \(0 \text{ to } 3500\) Fish production rises sharply, then growth rate slows after year 3.
Fertilizer cost trend Solid line with squares, decreasing from \(\$0.05 \text{ to } \$0.005\) Fertilizer costs decline steadily as fish production increases.
Series relationship Fish sold increases; fertilizer costs decrease Higher fish output (using apple by-products) reduces need for external inputs.

Key Insights

The dataset shows that integrating aquaculture with apple farming creates a beneficial feedback cycle. As fish production rises from \(0 \text{ to } 3500\) over five years, the cost of fertilizer per 10 kg of apples sold drops dramatically from \(\$0.05 \text{ to } \$0.005\). The average annual decrease in fertilizer cost is about \(\$0.01125 \text{ per year}\). The connection suggests fish waste effectively replaces externally purchased fertilizer. Fish production grows quickly in early years but the yearly increase slows after year 3 (from +1500/year to +500/year), indicating the system is maturing. Overall, the closed nutrient cycle increases profits by reducing outside costs and providing an additional product to sell.

Step-by-Step Solution

Question 1: Average Annual Decrease in Fertilizer Cost per 10 kg Apples

Complete Statement:

The average amount by which the cost of fertilizer per 10 kg of apples sold decreased from year 1 to year 5 is, to the nearest power of 10, nearest to _____ dollars per 10 kg apples per year.

Breaking Down the Statement
  • Statement Breakdown 1:
    • Key Phrase: average amount by which the cost... decreased
    • Meaning: We are being asked to find the yearly average reduction in fertilizer cost over a period of time.
    • Relation to Chart: We need to use the fertilizer cost data given for the years 1 to 5.
    • Important Implications: This involves both subtracting and averaging over the time period.
  • Statement Breakdown 2:
    • Key Phrase: from year 1 to year 5
    • Meaning: The calculation spans from the first to the fifth year.
    • Relation to Chart: We should read the cost values off the chart for year 1 and for year 5.
    • Important Implications: This is a time span of 4 years (\(5 - 1 = 4\)).

What is needed: The average yearly decrease in fertilizer cost per 10 kg apples, expressed as a single power of 10.

Solution:
  • Condensed Solution Implementation:
    Subtract the fertilizer cost at year 5 from that at year 1 to find the total decrease, then divide by 4 to find the yearly average, and round to the nearest power of 10.
  • Necessary Data points:
    Year 1 fertilizer cost: \(\$0.05\); Year 5 fertilizer cost: \(\$0.005\)
    • Calculations Estimations:
      Total decrease = \(\$0.05 - \$0.005 = \$0.045\); Years = 4; Average decrease = \(\$0.045 \div 4 = \$0.01125\)
    • Comparison to Answer Choices:
      \(\$0.01125\) is closest to 0.01 among the options provided.
FINAL ANSWER Blank 1: 0.01

Question 2: Rate of Growth in Fish Sold per Year after Year 3

Complete Statement:

After year 3, the rate of growth in the total number of fish sold per year was _____

Breaking Down the Statement
  • Statement Breakdown 1:
    • Key Phrase: After year 3
    • Meaning: We are concerned only with years 4 and 5, focusing on the trend following year 3.
    • Relation to Chart: Check the data points for fish sold in years 3, 4, and 5.
  • Statement Breakdown 2:
    • Key Phrase: rate of growth in the total number of fish sold per year
    • Meaning: This is the yearly increase in number of fish sold.
    • Relation to Chart: Calculate the differences in fish sold between consecutive years after year 3.

What is needed: Whether the annual increases in the number of fish sold after year 3 are getting larger, smaller, or staying about the same.

Solution:
  • Condensed Solution Implementation:
    Calculate and compare the increase from year 3 to 4, and from year 4 to 5.
  • Necessary Data points:
    Year 3: 2000 fish; Year 4: 3000 fish; Year 5: 3500 fish
    • Calculations Estimations:
      Increase 3→4: \(3000 - 2000 = 1000\); Increase 4→5: \(3500 - 3000 = 500\); The increase is getting smaller.
    • Comparison to Answer Choices:
      Because the increase drops from 1000 to 500 fish, the rate of growth is decreasing.
FINAL ANSWER Blank 2: Decreasing

Summary

To solve these blanks, we looked at the trend data on the chart for both fertilizer cost and number of fish sold. For the first blank, we calculated the average annual decrease (\(\$0.01125\)) and rounded to the nearest power of 10, which is 0.01. For the second blank, we saw the annual increase in fish sold dropped from 1000 to 500 after year 3, so the answer is Decreasing. Both require extraction and comparison of values rather than complicated calculations.

Question Independence Analysis

Question 1 concerns the fertilizer cost trend while Question 2 concerns the trend in fish sales. Each is about a different quantity, requiring different information, so the blanks are independent and can be solved separately.

Answer Choices Explained
The average amount by which the cost of fertilizer per 10 kg of apples sold decreased from year 1 to year 5 is, to the nearest power of 10, nearest to
1A
100
1B
10
1C
1
1D
0.01
1E
0.0001
dollars per 10 kg apples per year.
After year 3, the rate of growth in the total number of fish sold per year was
2A
Increasing
2B
Decreasing
2C
Constant
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An apple farm installed a fish pond on its land : Graphics Interpretation (GI)