An alloy, Alloy K, is made by mixing certain quantities of iron and lead. The total weight of the alloy...
GMAT Data Sufficiency : (DS) Questions
An alloy, Alloy K, is made by mixing certain quantities of iron and lead. The total weight of the alloy is \(50\text{ kg}\). What is the ratio of the weight of iron to the weight of lead in Alloy K?
- If \(4\text{ kg}\) of iron were to be replaced with \(4\text{ kg}\) of lead, the percentage of lead, by weight, in Alloy K would become \(40\%\).
- The weight of iron per \(100\text{ cc}\) is \(0.7\) times the weight of lead per \(100\text{ cc}\).
Understanding the Question
We need to find the ratio of the weight of iron to the weight of lead in Alloy K.
Given Information
- Alloy K contains only iron and lead
- Total weight = 50 kg
- If I = weight of iron and L = weight of lead, then \(\mathrm{I + L = 50}\)
What We Need to Determine
We need to find the ratio \(\mathrm{I:L}\) (or equivalently, \(\mathrm{I/L}\)). Since we know \(\mathrm{I + L = 50}\), if we can determine either I or L uniquely, we can find the other and thus determine the ratio.
For this question to be sufficient, we need to arrive at one specific ratio value.
Analyzing Statement 1
Statement 1: If 4 kg of iron were to be replaced with 4 kg of lead, the percentage of lead, by weight, in Alloy K would become 40%.
What Statement 1 Tells Us
This statement describes a hypothetical scenario. After replacing 4 kg of iron with 4 kg of lead:
- New amount of lead = \(\mathrm{L + 4}\) kg
- New amount of iron = \(\mathrm{I - 4}\) kg
- Total weight remains 50 kg (we're replacing, not adding)
- Lead would constitute exactly 40% of the total weight
Working Through the Logic
Since lead would be 40% of 50 kg after the replacement:
- \(\mathrm{L + 4 = 0.40 \times 50 = 20}\) kg
- Therefore, \(\mathrm{L = 16}\) kg (current amount of lead)
- Since \(\mathrm{I + L = 50}\), we get \(\mathrm{I = 34}\) kg (current amount of iron)
- The ratio \(\mathrm{I:L = 34:16 = 17:8}\) (dividing both by 2)
[STOP - Sufficient!] We can determine a unique ratio.
Conclusion
Statement 1 is sufficient.
This eliminates choices B, C, and E.
Analyzing Statement 2
Now let's forget Statement 1 completely and analyze Statement 2 independently.
Statement 2: The weight of iron per 100 cc is 0.7 times the weight of lead per 100 cc.
What Statement 2 Provides
This tells us about the density relationship between iron and lead:
- Density of iron = \(0.7 \times \mathrm{Density\,of\,lead}\)
In other words, iron is less dense than lead (which makes sense physically).
What We Still Don't Know
While we know the density relationship, we don't know:
- The actual volumes of iron and lead in the alloy
- Any constraint that would help us determine unique weights
Think of it this way: If we have 50 kg total, we could have:
- 30 kg iron + 20 kg lead (ratio \(3:2\))
- 25 kg iron + 25 kg lead (ratio \(1:1\))
- 40 kg iron + 10 kg lead (ratio \(4:1\))
The density relationship alone doesn't tell us which combination we actually have, because we don't know the volumes involved.
Conclusion
Statement 2 is NOT sufficient.
This eliminates choices B and D.
The Answer: A
Since Statement 1 alone is sufficient to determine the ratio, but Statement 2 alone is not sufficient, the answer is A.
Answer Choice A: "Statement 1 alone is sufficient, but Statement 2 alone is not sufficient."