Phase 1: Owning the Dataset
Visualization Selection
We'll use a comparison table since we're comparing properties of two distinct samples.
Creating Our Visual
| Property | Sample S1 | Sample S2 |
| Total Spores | ** (greater) | (less) |
| Pollen from Species P | ✓ (present) | not stated |
| Spores from Species Q | ✓ (present) | ✓ (all spores) |
| Total Species | (fewer) | ** (greater) |
Phase 2: Understanding the Question
Breaking Down the Statement
We need to complete: "S1 had the greater ratio of total number of 1 to total number of 2"
This means we're looking for: \(\frac{\mathrm{Something\ in\ S1}}{\mathrm{Something\ else\ in\ S1}} > \frac{\mathrm{Same\ something\ in\ S2}}{\mathrm{Same\ something\ else\ in\ S2}}\)
Key Insight
For S1 to have a greater ratio than S2:
- The numerator (position 1) should be something S1 has MORE of than S2
- The denominator (position 2) should be something S1 has LESS of than S2
- OR a combination that makes S1's ratio larger
What We Know for Certain
From our visualization:
- S1 has MORE total spores than S2 ✓
- S1 has FEWER species represented than S2 ✓
- S1 has pollen from Species P (S2's pollen status not mentioned)
Phase 3: Finding the Answer
Applying Our Logical Framework
Let's check which combination gives S1 a definitively greater ratio:
For position 1 (numerator): We need something S1 has more of
- "spores" - S1 has more ✓
- "pollen grains from Species P" - S1 has these, S2 not mentioned to have any
For position 2 (denominator): We need something S1 has less of
- "species represented" - S1 has fewer ✓
The Winning Combination
\(\mathrm{Ratio} = \frac{\mathrm{total\ spores}}{\mathrm{species\ represented}}\)
For S1: \(\frac{\mathrm{Many\ spores}}{\mathrm{Few\ species}} = \mathrm{Large\ ratio}\)
For S2: \(\frac{\mathrm{Few\ spores}}{\mathrm{Many\ species}} = \mathrm{Small\ ratio}\)
This perfectly satisfies our requirement that S1 has the greater ratio!
Phase 4: Solution
Position 1: spores
Position 2: species represented
This gives us: "S1 had the greater ratio of total number of spores to total number of species represented."
This answer emerges naturally from our data - S1 has both more spores (making the numerator larger) AND fewer species (making the denominator smaller), guaranteeing a greater ratio.