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A certain snail can travel at a rate of 1 text{ millimeter per second}. A children's storybook author wants to...

GMAT Two Part Analysis : (TPA) Questions

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Two Part Analysis
Quant - Core
MEDIUM
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A certain snail can travel at a rate of \(1 \text{ millimeter per second}\). A children's storybook author wants to convert this rate to other units to make the description more appealing to children.

Based on the given information, select for \(\mathrm{m/day}\) the closest to the equivalent speed of the snail in meters per day and select for \(\mathrm{km/wk}\) the closest to the equivalent speed of the snail in kilometers per week. Note that \(1 \mathrm{\;meter} = 1,000 \mathrm{\;millimeters}\) and \(1 \mathrm{\;kilometer} = 1,000 \mathrm{\;meters}\). Make only two selections, one in each column.

m/day
km/wk

0.6

29.4

86.4

604.2

4.2

Solution

Phase 1: Owning the Dataset

Visual Representation - Conversion Timeline

1 mm/s → [×60] → 60 mm/min → [×60] → 3,600 mm/hr → [×24] → ? mm/day → [÷1000] → ? m/day
                                                                    ↓
                                                                [×7 days]
                                                                    ↓
                                                                ? m/week → [÷1000] → ? km/week

Given Information

  • Snail speed: \(1 \mathrm{millimeter\,per\,second}\)
  • Conversion factors:
    • \(1 \mathrm{meter} = 1,000 \mathrm{millimeters}\)
    • \(1 \mathrm{kilometer} = 1,000 \mathrm{meters}\)
  • Answer choices: ["0.6", "29.4", "86.4", "604.2", "4.2"]

Phase 2: Understanding the Question

We need to find TWO values:

  1. m/day: The snail's speed in meters per day
  2. km/wk: The snail's speed in kilometers per week

The key insight: We'll convert step by step through time units, then through distance units.

Phase 3: Finding the Answer

Calculating m/day

Starting with \(1 \mathrm{mm/s}\):

  • Per minute: \(1 \times 60 = 60 \mathrm{mm/min}\)
  • Per hour: \(60 \times 60 = 3,600 \mathrm{mm/hr}\)
  • Per day: \(3,600 \times 24 = 86,400 \mathrm{mm/day}\)

Converting to meters:

  • \(86,400 \mathrm{mm} \div 1,000 = 86.4 \mathrm{meters\,per\,day}\)

✓ 86.4 is in our answer choices!

Calculating km/wk

Starting with our result of \(86.4 \mathrm{m/day}\):

  • Per week: \(86.4 \times 7 = 604.8 \mathrm{meters/week}\)

Converting to kilometers:

  • \(604.8 \mathrm{m} \div 1,000 = 0.6048 \mathrm{km/week}\)

The closest value in our choices is 0.6

Phase 4: Solution

Final Answer:

  • m/day: 86.4
  • km/wk: 0.6

Our systematic conversion shows the snail travels \(86.4 \mathrm{meters}\) in a day and approximately \(0.6 \mathrm{kilometers}\) in a week - both values that match our answer choices perfectly.

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